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Capstone Revison VD question 6

Capstone Revison VD question 6

by jake brown -
Number of replies: 0

hello,

Its saying its incorrect can you confirm please.. working out below 

vd= 5v divide spare root 3 

= 2.8v single phase therefore 11.5-2.8v = 8.7v drop fsc

vc = 1000xvd over (L x I)

vc = 1000x8.7 over (38 x 22) = 10.40 (single phase)

single phase to three phase 10.40 x 0.866 = 9.01

"in a conduit" (table 41) 75* max col

4mm2 = 9.71 round down 

6mm2 cable 

whats saying thats incorrect is find the max VC value for the cable