hello,
Its saying its incorrect can you confirm please.. working out below
vd= 5v divide spare root 3
= 2.8v single phase therefore 11.5-2.8v = 8.7v drop fsc
vc = 1000xvd over (L x I)
vc = 1000x8.7 over (38 x 22) = 10.40 (single phase)
single phase to three phase 10.40 x 0.866 = 9.01
"in a conduit" (table 41) 75* max col
4mm2 = 9.71 round down
6mm2 cable
whats saying thats incorrect is find the max VC value for the cable